SAP2000 tutorial course for beginners - 2: Materials definition and assigning loads
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Introduction:
This is the second SAP2000 tutorial, at the end of this tutorial you'll be able to define the materials and the properties of them (Steel, concrete, etc ..), and you will be able to assign the loads at any beam (point load, distributed trapizoidal, etc ..). Moreover, the section properties and materials will be taken into consideration because they affect the deflection and the structural elements self weight.
Materials definition:
Sections built on SAP must have an ID; materials are defined so program can calculate the self-weight of the members, and to design them in advance stage. To learn how to define materials follow these steps:
1- create a new project using blank template, do not forget to determine units before creating your new project.
2- From “Define option” choose: “Materials” (see figure 1).
2- From “Define option” choose: “Materials” (see figure 1).
[Fig.1] - Define- Materials selection |
3- First material to be defined will be concrete. To define a new material choose first option “Add new Material Quick” (See figure 2).
[Fig.2] - Add new quick material option |
3- From the drop window “material type” Choose concrete. Now click ok. Specifications option will be kept as default in this stage.
4- A new material “4000psi-1” is now defined. Highlight this new material and choose “Modify/show system” option to modify specifications. In this stage user will only change the name of material to be concrete instead of “psi4000-1”. Other options will be discussed later.
Now click ok to finish the definition of concrete material.
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Frame sections Definition:
Lines created in SAP must have section. Thus while viewing member with extrusion option you will see a 3d view of a section.To define a frame section follow these steps:
1- From define option choose option 2 “section proprieties” (see figure 1).
2- Choose “Frame Sections” option ➥ add new property ➥ select concrete instead of steel (see figure 4) ➥ Choose the geometry of the section (let us choose the simplest section [rectangular].
3- Change section name; usually section name includes dimensions: Rb×h.
Example: Rectangular section 50×60 is defined as R50×60.
4- To view section properties click at “Section Properties”. See figure 6.
[Fig.5] - Rectangular section definition |
4- To view section properties click at “Section Properties”. See figure 6.
Creating simple 2D structural system:
A simple 2D structural system consists of line elements (beams as an example), supports (pin supports as an example), loads.First stage will be learning how to create systems consisting of lines and supports, adding loads will be covered later.
Example 1: Use SAP2000 to create the simply supported beam shown in figure7.
[Fig.7] |
Steps for building this simple structural system:
1- Determine the view you are going to work in. in this example user will work in the XZ view.2- Build a Cartesian system consists of one spacing in the x direction. Indeed Cartesian system generates XY plane. No problem, user will only uses what he needs from grid system.
3- Cartesian system in this example will consist of 1 spacing in x, and 1 spacing in y. grid system must be as shown in figure 8.
4- Define concrete material, and section R50×60 (already defined).
5- Keep one window open and choose the XZ view.
6- Choose “Draw Frame/Cable Element “. Besides section option choose the section you want to use (see figure 9), then drag your mouse to point A and click then drag it again at point B and click to finish.
5- Keep one window open and choose the XZ view.
6- Choose “Draw Frame/Cable Element “. Besides section option choose the section you want to use (see figure 9), then drag your mouse to point A and click then drag it again at point B and click to finish.
7- If previous steps are done in a correct way, you must get the same result as shown in figure 10.
8- The final step is assigning supports. Since support at A is pin and support at B is roller (not the same support) we must select them separately. If they have common support multi selection is available.
9- After selecting point A ➥ Assign ➥ Joints ➥ Restraints ➥ Choose pin support (see figure 11).
[Fig.10] - Line R50×60 |
8- The final step is assigning supports. Since support at A is pin and support at B is roller (not the same support) we must select them separately. If they have common support multi selection is available.
9- After selecting point A ➥ Assign ➥ Joints ➥ Restraints ➥ Choose pin support (see figure 11).
10- Repeat same procedure to assign joint B.
Exercise 1: Draw structural system shown in figure 12. Distances are increasing from 1 to 6 (1,2,3,4,5,6).
Exercise 1: Draw structural system shown in figure 12. Distances are increasing from 1 to 6 (1,2,3,4,5,6).
[Fig.12] - Structural system for exercise |
Definition of loads on SAP2000:
Before assigning loads on structural system user must define load patterns. Load patterns expression stands for defining load families (Dead, Live, wind …etc). So the first step is defining the load patterns user want to apply to the structural system. Usually users are interested in defining load patterns like: Dead, Live, Wind. Following steps are done to define these three loads patterns.1- Define ➥ Load patterns ➥ Define load pattern window will appear (see Fig.12).
By default SAP2000 defines a load pattern with “self-weight multiplier”=1; this to include self-weight of the section in the analysis. If user modifies the self-weight multiplier to 0 then SAP will not include self-weight in analysis.
2- To define live load pattern set the mouse cursor in the space under load pattern name and delete DEAD and write LIVE, then from Type select live instead of dead. After doing these steps just click at: Add new load pattern (see figure 14).
2- To define live load pattern set the mouse cursor in the space under load pattern name and delete DEAD and write LIVE, then from Type select live instead of dead. After doing these steps just click at: Add new load pattern (see figure 14).
3- Finally user must have 3 load patterns as shown in figure 15.
Assigning Point load to a simply supported beam:
Example: Assign point loads to simply supported beam shown in figure 16.
1- Select the line ➥ Assign ➥ Frame Loads ➥ Point (see figure 17)
2- Write values as shown in figure 18. Remember to assign “Absolute distance from End-I”
[Fig.18] - Point load assignment 2 |
Assigning uniformly distributed load to a simply supported beam:
Example: Assign distributed loads (20 KN/m) shown in figure 19.
1- Select the line ➥ Assign ➥ Frame Loads ➥ distributed (see figure 20)
2- Write value as shown in figure 21.
Assigning Trapezoidal distributed load to a simply supported beam:
Example: Assign distributed loads (20 KN/m) shown in figure 22.
1- Select the line ➥ Assign ➥ Frame Loads ➥ distributed.
2- Write value as shown in figure 23.
2- Write value as shown in figure 23.
For the rest of the course:
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